∵ax²+bx+c=0（a、b、c是实数a≠0)∴a(x²+(b/a)x)+c=0a(x²+2(b/2a)x+(b/2a)²-(b/2a)²)+c=0a(x+b/2a)²-a(b/2a)²+c=0a(x+b/2a)²-b²/4a+c=0a(x+b/2a)²=b²/4a-c...