若14(a的二次方+b的二次方+c的二次方)=(a+2b+3c)的二次方,a=1,求b,c
人气:196 ℃ 时间:2019-10-10 03:13:42
解答
14*(a^2+b^2+c^2)=(a+2b+3c)^214a^2+14b^2+14c^2=a^2+4b^2+9c^2+4ab+6ac+12bc13a^2+10b^2+5c^2=4ab+6ac+12bca=113+10b^2+5c^2=4b+6c+12bc(c-3)^2+(b-2)^2+(3b-2c)^2=0c=3b=2
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