用二分法求方程0.8的x次方-1=lnx在区间（0,1）内的近似解 精确度0.3
人气：218 ℃ 时间：2020-03-26 00:46:56
解答
精确度0.下面按精确度0.01计算0.8^x-1=lnx设f(x)=0.8^x-1-lnxf(0.5)=0.5876>0f(0.9)=-0.07659<0取[0.5,0.9]的中点0.7f(0.7)=0.2121>0取[0.7,0.9]的中点0.8f(0.8)=0.05966>0取[0.8,0.9]的中点0.85f(0...
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