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化简sin(60°+2x)*cos(60°-2x)
人气:471 ℃ 时间:2020-06-13 15:04:54
解答
sin(60°+2x)*cos(60°-2x)
=1/2(sin(60°+2x+60°-2x)+sin(60°+2x-(60°-2x))
=1/2(sin120°+sin4x)
=1/2(√3/2+sin4x)
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