当a-b=5,ab=-1时,求(2a+3b-2ab)-(a+4b+ab)-(3ab+2b-2a)的值
人气:190 ℃ 时间:2019-10-17 14:19:25
解答
(2a+3b-2ab)-(a+4b+ab)-(3ab+2b-2a)
2a+3b-2ab-a-4b-ab-3ab-2b+2a
(2-1+2)a+(3-4-2)b+(-2-1-3)ab
3a-3b-6ab
3(a-b)-6ab
因为 a-b=5,ab=-1
所以.原式=3×5-6×(-1)=15+6=21
要先化简 ,然后把已知条件带到里面.
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