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(1)√12-√1/3=?(2)√8/2+2√18-1/4√32=?(3)√20×√5-8=?(4)(√8/27-5√6)×√6=?
人气:262 ℃ 时间:2019-11-23 11:07:43
解答
(1)√12-√1/3
=2√3-√3/3
=5√3/3;
(2)√8/2+2√18-1/4√32
=2√2/2+2×3√2-4√2/4
=√2+6√2-√2
=6√2;
(3)√20×√5-8
=2√5×√5-8
=2×5-8
=10-8
=2;
(4)(√8/27-5√6)×√6
=2√6/9×√6-5√6×√6
=12/9-30
=4/3-30
=-28-2/3
=-28又3分之2;
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