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已知xy=2,x-y=3,求(x+y)(x-y)-y^2-(6x^2y-2xy^2)/2y的值.
人气:154 ℃ 时间:2020-02-06 05:19:05
解答
x-y=3
(x-y)^2=9
x^2-2xy+y^2=9
x^2+y^2=13
(x+y)(x-y)-y^2-(6x^2y-2xy^2)/2y
=x^2-y^2-y^2-3x^2+xy
=-2(x^2+y^2)+xy
=-2*13+2
=-24
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