> 数学 >
已知xy=2,x-y=3,求(x+y)(x-y)-y^2+(x-y)^2-(6x^2y-2xy^2)/2y的值.
人气:240 ℃ 时间:2020-04-06 18:54:36
解答
(x+y)(x-y)-y^2+(x-y)^2-(6x^2y-2xy^2)÷2y =(x+y)(x-y)-y^2+(x-y)^2-2y(3x^2-xy)÷2y =(x+y)(x-y)-y^2+(x-y)^2-(3x^2-xy) =(x+y)(x-y)+(x-y)^2-y^2-(3x^2-xy) =[(x+y)+(x-y)](x-y)-y^2-(3x^2-x...
推荐
猜你喜欢
© 2025 79432.Com All Rights Reserved.
电脑版|手机版