化简:根号a³b²(a≥0,b≥0)
根号8a^4b^5 (a≥0,b≥0)
根号8x³+4x²z (x≥0,2x+z≥0)
根号3a²-12a+12 (a<2)
人气:241 ℃ 时间:2019-12-01 11:03:14
解答
1、√8a^4b^5 (a≥0,b≥0)√8a^4b^5=2a²b²√(2b).
2、√8x³+4x²z(x≥0,2x+z≥0)
√8x³+4x²z=√4x²(2x+z)=2x√(2x+z).
3、√(3a²-12a+12)(a<2)√(3a²-12a+12)=√3(a-2²)=√3(a-2)
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