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求积分 dx/(x+根号1-x2)
人气:484 ℃ 时间:2020-03-27 12:21:34
解答
令x=sint dx=costdt原式=∫costdt/(sint+cost)令A=∫costdt/(sint+cost) B=∫sintdt/(sint+cost)A+B=∫(sint+cost)dt/(sint+cost)=∫dt=t+C1A-B=∫(cost-sint)dt/(sint+cost)=∫d(sint+cost)/(sint+cost)=ln|sint+co...
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