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约分x^2-3xy+2y^2/-4x^2y^2+x^3y+4xy^3
人气:342 ℃ 时间:2020-09-17 16:29:59
解答
分子=x^2-3xy+2y^2=(x-y)(x-2y)
分母=-4x^2y^2+x^3y+4xy^3=xy(x^2-4xy+4y^2)=xy(x-2y)^2
所以,原式=[(x-y)(x-2y)]/[xy(x-2y)^2]=(x-y)/[xy(x-2y)]
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