已知x³=10-y³,x²y-xy²=-3,求代数式(x³-y³)(2x²y-4xy²)-2(-y³+xy²)的值.
人气：496 ℃ 时间：2019-10-19 13:45:10
解答
题目问的应该是（x^3-y^3)-(2x^2y-4xy^2)-2(-y^3+xy^2)的值x^3=10-y^3,x^2y-xy^2=-3则x^3+y^3=10,x^2y-xy^2=-3（x^3-y^3）-(2x^y-4xy^2)-2(-y^3+xy^2)=x^3-y^3-2x^y+4xy^2+2y^3-2xy^2=x^3+y^3-2x^y+2xy^2=(x^3+y^3)-...
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