(7x+3x^2)除以(2x+1)*(6x+3)除以(7x+3)
=(7x+3x^2)/(2x+1)*(6x+3)/(7x+3)
=x(7+3x)/(2x+1)*(3(2x+1)/(7x+3))
=3x(7+3x)/(7x+3)不能往下算了么不能再简化了，你看题目是不是(7x^2+3x)除以(2x+1)*(6x+3)除以(7x+3) =(7x^2+3x)/(2x+1)*(6x+3)/(7x+3) =x(7x+3)/(2x+1)*(3(2x+1)/(7x+3))=3x