m的平方/(m-2)+4/(2-m)
=m^2/(m-2)-4/(m-2)
=(m^2-4)/(m-2)
=(m+2)(m-2)/(m-2)
=m+2
当m=1/√（3-2）=1/1=1,
故原式=1+2=3.我打错了，应该是m=1/√3-2那就这样:当m=1/(√3-2）=(√3+2)/[(√3+2)(√3-2)]=(√3+2)/(3-2^2)=-√3-2故原式=-√3-2+2=-√3.