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计算lim根号下(7x^2-3sin^2x)/(4x+1)
x趋向于无穷大,根号下不包括分母。是sin平方x.
人气:364 ℃ 时间:2020-10-01 19:49:59
解答
lim根号下(7x^2-3sin^2x)/(4x+1)J = LIM(x→∞) √(7x^2-3sin^2x)/(4x+1)= LIM(x→∞) √(7x^2)/(4x)= √7/4 多写几步:√(7x^2-3sin^2x)/(4x+1)=√[x^2(7-3sin^2x/x^2)] / (4x+1)= x √[(7-3sin^2x/x^2)] / [x(4+1...
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