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lg2+lg5-lg1/2lg+lg8 x (lg32-lg2)过程与答案
(lg2+lg5-lg1)/(2lg+lg8) x (lg32-lg2)过程与答案 ,快,
人气:443 ℃ 时间:2020-04-04 12:17:18
解答
(lg2+lg5-lg1)/(2lg+lg8) x (lg32-lg2)
=( lg2 + lg5 - 0)/(lg2 + lg8) x (lg32 - lg2)
=lg(2 x 5)/lg(2 x 8) x lg (32÷2)
=lg10/lg16 xlg16
= 1
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