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因式分解:6xy+9x^2-m^2+y^2=?x^2·y-4y(x+y)^2+?
一直a^2+4b+b^2-2a+5=0,求a,b
人气:107 ℃ 时间:2020-03-22 12:15:59
解答
6xy+9x^2-m^2+y^2=(3x+y)²-m²=(3x+y+m)(3x+y-m)x^2·y-4y(x+y)^2=y*[x²-4(x+y)²]=y(x-2x-2y)(x+2x+2y)=-y(x+2y)(3x+2y) a^2+4b+b^2-2a+5=0,求a,ba²-2a+1+b²+4b+4=0(a-1)+(b+2)...
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