一个拱形 弧长C=89 拱形的高H=26 求它完整圆时半径R是多少?
Rn+1=(1-(Rn*COS(C/(2*Rn))-Rn+H)/((C/2)*SIN(C/(2*Rn))-H))*Rn
R0=30
R1=32.258
R2=32.486
R3=32.487
R4=32.487
R=32.487