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SIN^2 A+SIN^2 B-SIN^2 A*SIN^2 B+COS^2 A*COS^2 b等于 1
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人气:345 ℃ 时间:2020-04-20 20:02:11
解答
SIN^2 A+SIN^2 B-SIN^2 A*SIN^2 B+COS^2 A*COS^2 B
=SIN^2 A+SIN^2 B-SIN^2 A*(1-COS^2 A)+(1-SIN^2 A)*COS^2 B
=SIN^2 A+SIN^2 B-SIN^2 A+SIN^2 ACOS^2 A+COS^2 B-SIN^2 A*COS^2 B
=SIN^2 A+SIN^2 B-SIN^2 A+COS^2 B
=SIN^2 B+COS^2 B
=1
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