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初二数学题约分下列式子
36a^3(x-y)^2/27a(y-x),6(-a)^3/-4a^2b
人气:338 ℃ 时间:2020-02-19 08:53:45
解答
36a^3(x-y)^2/27a(y-x)
=36a³(x-y)²/[-27a(x-y)]
=-4/3*a²(x-y)
,6(-a)^3/-4a^2b
=-6a³/(-4a²b)
=-2a²*3a/(-2a²*b)
=3a/b
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