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(16-x^2)/(x^2+8x+16)÷(x-4)/(2x+8)×(x-2)/(x+2)
人气:281 ℃ 时间:2020-02-05 20:38:41
解答
(16-x^2)/(x^2+8x+16)÷(x-4)/(2x+8)×(x-2)/(x+2)
=(4+x)(4-x)/(x+4)^2×2(x+4)/(x-4)×(x-2)/(x+2)
=-2(x-2)/(x+2)
=-2x-4/x+2
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