化简~(x²+3x+9/x²-27)+(6x/9x-x²)-(x-1/6+2x)
(x²+3x+9/x²-27)+(6x/9x-x²)-(x-1/6+2x)
注意了!是三个分式!
(x²+3x+9)/(x²-27)+(6x)/(9x-x²)-(x-1)/(6+2x)
人气：187 ℃ 时间：2020-05-19 03:37:47
解答
（X²+3X+9/X²-27)+(6X/9X-X²)-(X-1/6+2X)
=X²+3X+9/X²-27+6/9-X²-X+1/6+2X
=9/X²-157/6
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