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(log2 3+log4 9+log8 27+...+log2^n 3^n)log9 32的N次方根
人气:380 ℃ 时间:2020-09-02 22:36:48
解答
log4 9=2lg3/2lg2 =lg3/lg2=log2 3
log2 3+log4 9+log8 27+...+log2^n 3^n
=nlog2 3=nlg3/lg2
log9 32的N次方根
(log2 3+log4 9+log8 27+...+log2^n 3^n)log9 32的N次方根=(1/n)(5lg2/2lg3)*nlg3/lg2
=5/2
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