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lim sin(x-2)/x^2-5x+6=?
要等价无穷小过程
人气:247 ℃ 时间:2020-02-05 14:14:51
解答
lim(x→2) sin(x-2)/x^2-5x+6
=lim(x→2) (x-2)/(x-2)(x-3) * lim(x→2) sin(x-2)/(x-2).这一步是等价无穷小
=lim(x→2) 1/(x-3) * 1
=-1
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