f(x)=[(cosx)^2-(sinx)^2]+√3sin2x=cos2x+√3sin2x=2sin(2x+π/6),最小正周期T=π,由-π/2+2kπ≤2x+π/6≤π/2+2kπ,k∈Z解得：-π/3+kπ≤x≤π/6+kπ,k∈Z,故：函数fx的最小正周期是π；单调递增区间是：[-π/3+...