f(x)=2cosx(sinxcosπ/6+sinπ/6cosx)-1/2=√3sinxcosx+cos²x-1/2=(√3/2)sin2x+(cos2x+1)/2-1/2=(√3/2)sin2x+(1/2)cos2x=sin(2x+π/6);所以最小正周期T=2π/2=π;如需编辑回答或插入图片,请点击标题到问题详...