题目应是〔(x+2/x²-2x）-（x-1/x²-4x+4)〕÷2-4/x³-2x²
=〔(x+2/x(x-2）-（x-1/(x-2)²)〕÷2-4/x³-2x²
=〔(x+2)(x-2）-x(x-1)]/x(x-2)² ÷2-4/x³-2x²
=〔x²-4-x²+x]/x(x-2)² ÷2-4/x³-2x²
=(x-4)/2x(x-2)² -4/x²(x-2)
=[x(x-4)-8(x-2)]/2x²(x-2)²
=[x²-4x-8x+16]/2x²(x-2)²
=[x²-12x+16]/2x²(x-2)²