已知函数f(x)=asin(ωχ+π/3),g(x)=btan(ωχ-π/3）（ω＞0)的最小正周期之和为3π/2,且f(π/2)_数学解答

已知函数f(x)=asin(ωχ+π/3),g(x)=btan(ωχ-π/3）（ω＞0)的最小正周期之和为3π/2,且f(π/2)=g(π/2
f(π/4)+√3g(π/4）=1,求f(x)g(x)的解析式
求f(x)和g(x)的解析式

人气：211 ℃　时间：2020-01-29 20:27:23

解答

由f(x)和g(x)的最小正周期之和为3π/2得2π/ω +π/ω =3π/2得ω =2由f(π/2)=g(π/2)得-asin(π/3)=-btan(π/3）得a=2bf(x)=2bsin(2χ+π/3),g(x)=btan(2χ-π/3）（ω＞0)由f(π/4)+√3g(π/4）=1得2bCosπ/3+√3...