1/[(n+1)n/2]
=2/n(n+1)
=2*[1/n-1/(n+1)]
所以原式=2*[1-1/2+1/2-1/3+1/3-1/4+……+1/n-1/(n+1)]
=2*[1-1/(n+1)]
=2n/(n+1)