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(急求)求函数y=sinx+sin(x-π/3)的周期及值域
人气:233 ℃ 时间:2020-04-22 02:16:19
解答
y=sinx+sin(x-π/3)
=2sin(x-π/6)cos(π/6)
=√3sin(x-π/6)
T=2π,
-√3≤y≤√3
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