已知,如图,在三角形ABC中,角ACB=90度,AE=AC,BD=BC,求证:角DCE=45°
人气:138 ℃ 时间:2019-11-13 04:13:39
解答
因为AE=AC,BD=BC 所以∠AEC=∠ACE,∠BDC=∠BCD 又因为∠ACB=90° 所以∠A加∠B等于90° ∵∠AEC=(180-∠A)÷2 ∠BDC=(180-∠B)÷2 ∴∠DCE={180-(180-∠A)÷2-(180-∠B)÷2 又∵∠A加∠B等于90° ∴∠DCE=45°请采纳回答,
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