x=1/x x²=1
X-3分之X的平方-6X+9 再除以X的平方+6X+9分之X+3的值
[(x²-6x+9)/(x-3)]/[(x+3)/(x²+6x+9)]
=[(x²-6x+9)(x²+6x+9)]/[(x-3)(x+3)]
=[(x²+9)²-36x²]/(x²-9)
=(100-36)/(1-9)
=64/(-8)
=-8