(x+1)分之1-(x²-6x+9)分之(3-x)÷(x-3)分之(x²+x)=(x+1)分之1-(x-3)²分之[-(x-3)]÷(x-3)分之[x(x+1)]=(x+1)分之1+(x-3)分之1×[x(x+1)]分之(x-3)=(x+1)分之1+[x(x+1)]分之1=[x(x+1)]分之x+[x(x+1)]...