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解二元二次方程组:6x^2-5xy+y^2=0 ,x^2+xy+y^2=7
人气:159 ℃ 时间:2019-08-19 03:53:39
解答
6x^2-5xy+y^2=0 (1)x^2+xy+y^2=7 (2)由(1)得:(3x-y)(2x-y)=0,3x-y=0,2x-y=0y=3x(3)或y=2x(4)把(3)(4)分别代入(2)得:x^2+3x^2+9x^2=7,13x^3=7,x=±7√91x^2+2x^2+4x^2=7,7x^2=7,x=±1分别代入(3)(4)得方程组...
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