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xSn=x^2+2x^3+…nx^(n+1) 与Sn=x+2x^2+3x^3+…nx^n相减 等于多少
人气:174 ℃ 时间:2020-05-15 22:39:47
解答
xSn-Sn
=(x^2+2x^3+…nx^(n+1))-(x+2x^2+3x^3+…nx^n
)
=-x-x^2-x^3-..-x^n+nx^(n+1)
=-x(x^(n+1)-1)/(x-1)+nx^(n+1)
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