√2 / (1+i) = √2(1-i) / 2 = √2/2 - √2/2 i = cos(π/4) - i sin(π/4) = cos(-π/4) + i sin(-π/4) = e^(-π/4i)所以[√2 / (1+i) ]^3204 = e^(-π/4i) ^ 3204 = e^(-801πi) = e^(-πi) = cos(-π) + isin(-...