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数学
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∫(1/(1+e∧-x))dx的不定积分怎么算
人气:307 ℃ 时间:2020-05-02 01:41:08
解答
∫ 1/(1 + e^-x) dx
= ∫ 1/(1 + 1/e^x) dx
= ∫ e^x/(e^x + 1) dx
= ∫ d(e^x + 1)/(e^x + 1)
= ln(e^x + 1) + C
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