帮我算几道简单的数学题
每项的系数是多少:-1/8-a^2h+3π 注:π是3.14
简化求值:1/2x+(-3/2x+1/3y^2)-(2x-2/3y^2),其中x=-1/3,y=2/3
x(x+2y)-(x+1)^2+2x ,其中x=1/25,y=-25
人气:278 ℃ 时间:2020-02-06 10:51:18
解答
每项的系数是多少:-1/8(系数:-1/8)-a^2h(系数:-1)+3π(系数:3π); 注:π是3.14 简化求值:1/2x+(-3/2x+1/3y^2)-(2x-2/3y^2),其中x=-1/3,y=2/3 原式=(1/2x-3/2x-2x)+(1/3y^2+2/3y^2)=(-3x)+y^2=-3*(-1/3)...
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