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计算极限lin下x→3=sin(x-3)/x平方-2x-3
人气:362 ℃ 时间:2020-05-27 13:06:12
解答
x→3则x-3→0
sin(x-3)~x-3
lim下x→3 sin(x-3)/(x^2-2x-3)
=limx→3 (x-3)/(x-3)(x+1)
=limx→3 1/(x+1)
=1/4
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