解
4x²+9y²-4x-6y+2=0
(4x²-4x+1)+(9y²-6y+1)=0
(2x-1)²+(3y-1)²=0
∴2x-1=0,3y-1=0
∴x=1/2,y=1/3
∴√xy分之1
=√1/(1/2×1/3)
=√1/(1/6)
=√6