已知{(x²+y²)-(x-y)²+2y(x-y)}÷4y=1,求4x²-y²分_数学解答

已知{(x²+y²)-(x-y)²+2y(x-y)}÷4y=1,求4x²-y²分之4x -- 2x+y分之1 的值!

人气：216 ℃　时间：2019-10-17 03:22:58

解答

{(x²+y²)-(x-y)²+2y(x-y)}÷4y=1{x²+y²-(x²-2xy+y²)+2xy-2y²}÷4y=1{x²+y²-x²+2xy-y²+2xy-2y²}÷4y=1{4xy-2y²}÷4y=12y{2x-y}÷4y=1{2x-y}...