f(x)=2sin²(ωx)＋2sin(ωx)cos(ωx)=1－cos(2ωx)＋sin(2ωx)=√2sin(2ωx－π/4)＋1
1、T=2π/|2ω|=π,则ω=1；
2、f(x)=2sin(2x－π/4)＋1,则2x－π/4∈[－π/4,13π/12],f(x)∈[－√2＋1,3].