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分式数学问题
1.
已知x+1/y=z+1/x=1,求y+1/z的值
2.
解方程:(x-4)/(x-5) - (x-5)/(x-6) = (x-7)/(x-8) - (x-8)(x-9)
人气:339 ℃ 时间:2020-03-24 13:33:27
解答
x + 1/y = 1 则:y = 1/(1-x)z + 1/x = 1 则:z = 1- 1/x = (x-1)/x ,所以,1/z = x/(x-1) = 1+ 1/(x-1) = 1-1/(1-x)所以 y + 1/z = 1(x-4)/(x-5) - (x-5)/(x-6) = (x-7)/(x-8) - (x-8)(x-9)即:1+1/(x-5) - 1 - 1/(x...
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