动点为(x,y)
(x-3)²+(y+5)²=(x-2)²+(y-4)²,则x²-6x+9+y²+10y+25=x²-4x+4+y²-8y+16.整理,得
9y-x+7=0
故动点的轨迹方程为：9y-x+7=0