the minimum value of y=x^3-x on the interval (0,1)
how to find the minimum and maximum values for the function like:y=ax^3-bx?
人气：161 ℃ 时间：2020-06-10 23:09:18
解答
the most simple method is to find the derivative of the function.
y'= 3x^2-1
thus whenever x∈(0,sqrt(1/3)) the derivative y'(x)
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