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先化简再求值(a-2ab-b²/a)乘以a²+ab/a²-b²其中a=1,-3小于b小于负根号三且b为整数
人气:334 ℃ 时间:2020-04-10 10:02:21
解答
a=1,-3小于b小于负根号三且b为整数,b=-2(a-2ab-b²)/a乘以(a²+ab)/(a²-b²)=(a-2ab-b²/a乘以a(a+b)/[(a+b)(a-b)]=(a-2ab-b²)/(a-b)=(1-2b-b²)/(1-b)=(1+4-4)/(1+2)=1/3...
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