help!(2+1)(2^2-1)(2^4+1).(2^32+1)等于多少?(2^2是2的平方)已知a+1/a=10,求(a-1/_数学解答

help!
(2+1)(2^2-1)(2^4+1).(2^32+1)等于多少?(2^2是2的平方)
已知a+1/a=10,求(a-1/a)的值.(1/a是a分之1)
(请务必说清楚理由,

人气：490 ℃　时间：2020-04-14 07:26:10

解答

(2+1)(2^2+1)(2^4+1).(2^32+1)
=(2-1)(2+1)(2^2+1)(2^4+1)...(2^32+1)
=(2^2-1)(2^2+1)(2^4+1)...(2^32+1)
=.
=(2^32-1)(2^32+1)
=2^64-1
a+1/a=10
[a-1/a]^2=[a+1/a]^2-4=10*10-4=96
a-1/a=+/-根96=+/-4根6