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【高数微积分】求下列极限 limx→∞[lg(x^2=100)/(100x^2+1)]
= 偶写错了
limx→∞[lg(x^2+100)/(100x^2+1)]
人气:288 ℃ 时间:2020-05-23 23:23:10
解答
(x^2=100)/(100x^2+1(1-100/x^2)/(100+1/x^2),当x趋于无穷时,极限为1/100,取对数后极限为-2
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