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因式分解法解下列方程 1.X²-7X+6=0 2.(5X-1)²=3(5X-1) 3.(2X-5)²-(X+4)²=0
因式分解法解下列方程
1.X²-7X+6=0
2.(5X-1)²=3(5X-1)
3.(2X-5)²-(X+4)²=0
人气:339 ℃ 时间:2020-04-15 22:37:30
解答
1.X²-7X+6=0
(X-6)(X-1)=0
X1=6 X2=1
2.(5X-1)²=3(5X-1)
(5X-1)²-3(5X-1)=0
(5X-1)(5X-1-3)=0
X1=1/5 X2=4/5
3.(2X-5)²-(X+4)²=0
4X²-20X+25-X²-8X-16=0
3X²-28X+9=0
(3X-1)(X-9)=0
X1=1/3 X2=9
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