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lim(x→负∞)根号下(x^2+3x+1)减 根号下(x^2-x+1)=
人气:396 ℃ 时间:2020-04-14 07:11:24
解答
设极限式为A,1/x = -y,则y-inf,y->0A = [(x^2+3x+1) - (x^2-x+1) ]/ [ sqrt(x^2+3x+1) + sqrt(x^2-x+1)]分子分母同除以x,则A = (4 + y)/-[sqrt(1 - 3y + y^2) + sqrt(1 +y +y^2)]limA = -2
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